Giving the funtion
[tex](4m^{-3}n^2)^2[/tex]m=2
n=-3
[tex](4(2)^{-3}(-3)^2)^2[/tex][tex](\frac{4}{2^3}(9))^2[/tex][tex](\frac{36}{2^3})^2[/tex][tex](\frac{36^2}{2^6})[/tex][tex](\frac{2^49^2}{2^2*2^4})=\frac{9^2}{2^2}[/tex][tex]\frac{81}{4}[/tex]then the evaluated function in m=2 n=-3
has a value of 81/4