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A truck enters a stretch of road that drops 4 meters
in elevation for every 100 meters along the length of
the road. The road is at 1,300 meters elevation where
the truck entered, and the truck is traveling at
16 meters per second along the road. What is the
elevation of the road, in meters, at the point where
the truck passes t seconds after entering the road?

Respuesta :

1300 - 0.64t Answer<

m = -4m/ 100m = -.04

1300 - .04 (16) (t)

Meters - .04 (Meters / sec.) (sec.)
Cricetus

The elevation of the road will be "1300-0.64t".

According to the question,

Speed of truck,

  • 16 m/s

Distance covered by truck in t seconds,

  • x = 16t

Drop of,

  • 4 m

Let,

  • Truck entered at x = 0.
  • Elevation or height be "y".

Now,

→ The drop per meter:

= [tex]\frac{4}{100}[/tex]

→ The drop for 16t length:

= [tex]\frac{4\times 16t}{100}[/tex]

= [tex]0.64 t[/tex]

hence,

→ [tex]Elevation = Initial \ elevation - Drop[/tex]

                   [tex]= 1300-0.64 t[/tex]

Thus the above answer is right.

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https://brainly.com/question/20268108

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