delincuent7369 delincuent7369
  • 03-06-2020
  • Mathematics
contestada

The segments are tangents to the circle. Find the perimeter of JLNQ.

The perimeter of the polygon is

Respuesta :

Newton9022 Newton9022
  • 05-06-2020

Answer:

36 Units.

Step-by-step explanation:

In the diagram attached, K, M, P and R are points of tangency.

Theorem: Tangents to a circle from the same point are equal.

By the theorem above,

LK=LM=6 Units

NM=NP=2 Units

QP=QR=7 Units

JR=JK=3 Units

Therefore:

JL=JK+KL=3+6=9 Units

LN=LM+LN=6+2=8 Units

NQ=NP+PQ=2+7=9 Units

QJ=QR+RJ=7+3=10 Units

Therefore, the perimeter of the polygon JLNQ =9+8+9+10

=36 Units.

Note: The second diagram shows the theorem already applied.

Ver imagen Newton9022
Ver imagen Newton9022
Answer Link

Otras preguntas

What is the answer to this problem
Alkanes are hydrocarbons that contain what type of bonds
You must _____ the recording of the macro when you have completed the tasks it was designed to do
Refer to wal-mart. the addition of the corporate compliance department reflects the implementation of a(n) ____.
State two applications of plane mirrors
Write 3x(x+4)(x-1) in standard form.
The seventh-grade class is building target areas for a PE activity. The bases for the game will be circular in shape. The diameter of each circle is 5 feet. App
please help!!!!! What problem or debate did federalism help solve? EXPLAIN
Is the following a Proportion 15/40 = 5/8
5 √8 √8/3√8^5 Can someone explain this please??  Am I doing this right.  =8 1/5 8 1/2 divided by (8 1/3)^5  then I get stuck