Inrt9404 Inrt9404
  • 03-06-2020
  • Mathematics
contestada

When a number is increased by 28%, the result is 47. What is the original number to the nearest tenth?

Respuesta :

joaobezerra joaobezerra
  • 05-06-2020

Answer:

The original number was 36.7.

Step-by-step explanation:

Multipliers:

The multiplier for a increase of a% is 1 + a/100.

The multiplier for a decrease of b% is 1 - b/100.

In this question:

The original value is x.

Increased by 28%, so we have that 1 + (28/100) = 1.28x. Equals 47. We have to find x.

1.28x = 47

x = 47/1.28

x = 36.7

The original number was 36.7.

Answer Link

Otras preguntas

Lizabeth earned $126 for 6 hours of work. The equation 6h=126 can be used to find h the amount earns in one hour. How much did lizabeth earn in one hour
What is a good example of a piece of American pop culture entertainment? ( It could be a movie or tv show or game) Your answer should include: 1. The name of t
A bakery offers a sale price of $3.25 for 4 muffins. What is the price per dozen?
[tex]7x - 14 = 0[/tex]​
What is the value of the expression below? ​| 10 | - | - 3 |
How is declarative memory different procedural memory
SOME ONE PLZZZZ HELP!
why a single ovum is produced by oogenesis
the slope of (-3,7) and (2,-3)
What is meant by full grain?